Encora interview questions

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Encora interview questions

my answer for SQL was this :)

Select e.depid,d.name from dep d,emp e, (select p.id from proj groupby e.depid having count(e.depid>0)) as proj

 where e.depid=d.id and proj.id=e.projid groupby e.depid having count(e.depid>0)

Smashplus

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